In this civil engineering article, you will learn how to work out the reinforcement quantity in foundation & column.

The dimension of the footing is given as 3000 mm x 3000 mm. The size of the column is 300 mm x 300 mm.

The cross section of the column is given as follow :-

Depth = 300 mm

The dimension of the main concrete = 100 mm

The distance among two bars = 200 mm c/c (for both sides) with 12 mm dia

The height from plinth level to top of the column is 3 meter

Now, the length of each bar in the x-axis can be calculated as follow :-

Length = 3000 – side covers + (2 x 300) – 2 covers (top & bottom)

L = 3000 – (2 x 50) + 600 – (2 x 50)

L = 2900 + 500 = 3400 mm or 3.4 meters

The numbers of steel bars in x-axis will be calculated as follow :-

Nos = 3000 – 2 sides covers + 1 / spacing

Nos = 3000 – (2 x 50) / 200 + 1

Nos = 14.5 = 15 numbers approx.

Now, the unit weight of steel per meter will be computed as follow :-

Unit Weight of steel per meter = D2 / 162 = (12 x 12) / 162 = 0.88 kg / meter (for 12 mm dia bar)

Unit Weight of steel per meter = D2 / 162 = (16 x 16) / 162 = 1.58 kg / meter (for 16 mm dia bar)

Here D stands for the diameter of bars.

Now, the length of bars in y axis will be calculated as follow :-

L = 3000 +700 + 300 – covers + 300 (bent of bars) + 300 – 2 covers

L = 3000 +700 + 300 – 50 + 300 + 300 – 2 x 50 = 5000 mm or 5 m