In this exclusive construction video tutorial, you will get some useful guidelines to verify whether the column is capable of withstanding the enforced load or force.

In this civil engineering video tutorial, the solution is given to the following problem:-

Will the following mild steel column be able to bear 1500 kips load?

The height of the column is given as L = 8 feet

Cross section = 10 x 10 inches

Both the ends of the column are pinned or hinged.

To provide the solution of the above problem, initially it is required to examine the column for compression and check the column for buckling.

Check for compression:-

Stress (due to outside load on the given column) = load| force / s area [are means cross sectional area]

After putting all the values, we get the following result:-

1500 / 10 x 10 = 15 ksi

So, the stress is 15 ksi

If the permissible stress is greater than internal stress due to outside force, then the condition of the column is perfect against compression.

Suppose, the mild steel is just at 36

So, the permissible stress is 36 ksi and internal stress is 15 ksi i.e. the permissible stress is greater than internal stress.

Examining the column for buckling

To perform this, use the Euler’s buckling load formula:-

Π²EI / l²

Here, E denotes modulus of elasticity of materials

I denote moment of inertia about centriod

l denotes effective length of the column

To learn the detail calculation process, go through the following video tutorial.

Video Courtesy : Engineer Boy